(4x-1)/2x=5

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Solution for (4x-1)/2x=5 equation:


x in (-oo:+oo)

x*((4*x-1)/2) = 5 // - 5

x*((4*x-1)/2)-5 = 0

(x*(4*x-1))/2-5 = 0

(x*(4*x-1))/2+(-5*2)/2 = 0

x*(4*x-1)-5*2 = 0

4*x^2-x-10 = 0

4*x^2-x-10 = 0

4*x^2-x-10 = 0

DELTA = (-1)^2-(-10*4*4)

DELTA = 161

DELTA > 0

x = (161^(1/2)+1)/(2*4) or x = (1-161^(1/2))/(2*4)

x = (161^(1/2)+1)/8 or x = (1-161^(1/2))/8

(x-((1-161^(1/2))/8))*(x-((161^(1/2)+1)/8)) = 0

((x-((1-161^(1/2))/8))*(x-((161^(1/2)+1)/8)))/2 = 0

((x-((1-161^(1/2))/8))*(x-((161^(1/2)+1)/8)))/2 = 0 // * 2

(x-((1-161^(1/2))/8))*(x-((161^(1/2)+1)/8)) = 0

( x-((1-161^(1/2))/8) )

x-((1-161^(1/2))/8) = 0 // + (1-161^(1/2))/8

x = (1-161^(1/2))/8

( x-((161^(1/2)+1)/8) )

x-((161^(1/2)+1)/8) = 0 // + (161^(1/2)+1)/8

x = (161^(1/2)+1)/8

x in { (1-161^(1/2))/8, (161^(1/2)+1)/8 }

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