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(4x-1)-3x=5/4-(x+2)
We move all terms to the left:
(4x-1)-3x-(5/4-(x+2))=0
Domain of the equation: 4-(x+2))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-(x+2))!=-4
x∈R
-3x+(4x-1)-(5/4-(x+2))=0
We get rid of parentheses
-3x+4x-(5/4-(x+2))-1=0
We multiply all the terms by the denominator
-3x*4-(x+2))+4x*4-(x+2))-(5-1*4-(x+2))=0
We add all the numbers together, and all the variables
-3x*4-(x+2))+4x*4-(x+2))-(5-1*4-(x=0
Wy multiply elements
-12x-(x+2))+4x*4-(x+2))-(5-1*4-(x=0
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