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(4x-1)(3x+5)=-5
We move all terms to the left:
(4x-1)(3x+5)-(-5)=0
We add all the numbers together, and all the variables
(4x-1)(3x+5)+5=0
We multiply parentheses ..
(+12x^2+20x-3x-5)+5=0
We get rid of parentheses
12x^2+20x-3x-5+5=0
We add all the numbers together, and all the variables
12x^2+17x=0
a = 12; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·12·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*12}=\frac{-34}{24} =-1+5/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*12}=\frac{0}{24} =0 $
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