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(4x-0.7)(2x+0.1)=90
We move all terms to the left:
(4x-0.7)(2x+0.1)-(90)=0
We multiply parentheses ..
(+8x^2+0.4x-1.4x-0.07)-90=0
We get rid of parentheses
8x^2+0.4x-1.4x-0.07-90=0
We add all the numbers together, and all the variables
8x^2-1x-90.07=0
a = 8; b = -1; c = -90.07;
Δ = b2-4ac
Δ = -12-4·8·(-90.07)
Δ = 2883.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{2883.24}}{2*8}=\frac{1-\sqrt{2883.24}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{2883.24}}{2*8}=\frac{1+\sqrt{2883.24}}{16} $
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