(4x+x+x)+(16-12+10)=180

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Solution for (4x+x+x)+(16-12+10)=180 equation: 



(4x+x+x)+(16-12+10)=180

We move all terms to the left:

(4x+x+x)+(16-12+10)-(180)=0

determiningTheFunctionDomain
(4x+x+x)-180+(16-12+10)=0

We add all the numbers together, and all the variables

(+6x)-180+14=0

We add all the numbers together, and all the variables

(+6x)-166=0

We get rid of parentheses

6x-166=0

We move all terms containing x to the left, all other terms to the right

6x=166

x=166/6

x=27+2/3

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