(4x+80)+108+2x=180

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Solution for (4x+80)+108+2x=180 equation: 



(4x+80)+108+2x=180

We move all terms to the left:

(4x+80)+108+2x-(180)=0

We add all the numbers together, and all the variables

2x+(4x+80)-72=0

We get rid of parentheses

2x+4x+80-72=0

We add all the numbers together, and all the variables

6x+8=0

We move all terms containing x to the left, all other terms to the right

6x=-8

x=-8/6

x=-1+1/3

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