(4x+8)+(x2)=180

Solution for (4x+8)+(x2)=180 equation:

(4x+8)+(x2)=180

We move all terms to the left:

(4x+8)+(x2)-(180)=0

We add all the numbers together, and all the variables

x^2+(4x+8)-180=0

We get rid of parentheses

x^2+4x+8-180=0

We add all the numbers together, and all the variables

x^2+4x-172=0

a = 1; b = 4; c = -172;
Δ = b2-4ac
Δ = 42-4·1·(-172)
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{11}}{2*1}=\frac{-4-8\sqrt{11}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{11}}{2*1}=\frac{-4+8\sqrt{11}}{2}
$