(4x+7)x=(2x-1)x

Solution for (4x+7)x=(2x-1)x equation:

(4x+7)x=(2x-1)x

We move all terms to the left:

(4x+7)x-((2x-1)x)=0

We multiply parentheses

4x^2+7x-((2x-1)x)=0


We calculate terms in parentheses: -((2x-1)x), so:

(2x-1)x

We multiply parentheses

2x^2-1x

Back to the equation:

-(2x^2-1x)


We get rid of parentheses

4x^2-2x^2+7x+1x=0

We add all the numbers together, and all the variables

2x^2+8x=0

a = 2; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·2·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*2}=\frac{0}{4}
=0
$