(4x+7)+(2x-5)=28

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Solution for (4x+7)+(2x-5)=28 equation:



(4x+7)+(2x-5)=28
We move all terms to the left:
(4x+7)+(2x-5)-(28)=0
We get rid of parentheses
4x+2x+7-5-28=0
We add all the numbers together, and all the variables
6x-26=0
We move all terms containing x to the left, all other terms to the right
6x=26
x=26/6
x=4+1/3

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