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(4x+7)(x)=480
We move all terms to the left:
(4x+7)(x)-(480)=0
We multiply parentheses
4x^2+7x-480=0
a = 4; b = 7; c = -480;
Δ = b2-4ac
Δ = 72-4·4·(-480)
Δ = 7729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{7729}}{2*4}=\frac{-7-\sqrt{7729}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{7729}}{2*4}=\frac{-7+\sqrt{7729}}{8} $
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