(4x+6)=(x+1)+(x+15)

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Solution for (4x+6)=(x+1)+(x+15) equation: 



(4x+6)=(x+1)+(x+15)

We move all terms to the left:

(4x+6)-((x+1)+(x+15))=0

We get rid of parentheses

4x-((x+1)+(x+15))+6=0



We calculate terms in parentheses: -((x+1)+(x+15)), so:

(x+1)+(x+15)

We get rid of parentheses

x+x+1+15

We add all the numbers together, and all the variables

2x+16

Back to the equation:

-(2x+16)



We get rid of parentheses

4x-2x-16+6=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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