(4x+6)+(4x+5)+(4x)=(5x+8)+(4x)+(4x)

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Solution for (4x+6)+(4x+5)+(4x)=(5x+8)+(4x)+(4x) equation: 



(4x+6)+(4x+5)+(4x)=(5x+8)+(4x)+(4x)

We move all terms to the left:

(4x+6)+(4x+5)+(4x)-((5x+8)+(4x)+(4x))=0

We add all the numbers together, and all the variables

4x+(4x+6)+(4x+5)-((5x+8)+4x+4x)=0

We get rid of parentheses

4x+4x+4x-((5x+8)+4x+4x)+6+5=0



We calculate terms in parentheses: -((5x+8)+4x+4x), so:

(5x+8)+4x+4x

We add all the numbers together, and all the variables

8x+(5x+8)

We get rid of parentheses

8x+5x+8

We add all the numbers together, and all the variables

13x+8

Back to the equation:

-(13x+8)



We add all the numbers together, and all the variables

12x-(13x+8)+11=0

We get rid of parentheses

12x-13x-8+11=0

We add all the numbers together, and all the variables

-1x+3=0

We move all terms containing x to the left, all other terms to the right

-x=-3

x=-3/-1

x=+3

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