(4x+58)=(20x-52)/2

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Solution for (4x+58)=(20x-52)/2 equation: 



(4x+58)=(20x-52)/2

We move all terms to the left:

(4x+58)-((20x-52)/2)=0

We get rid of parentheses

4x-((20x-52)/2)+58=0

We multiply all the terms by the denominator


4x*2)-((20x-52)+58*2)=0

We add all the numbers together, and all the variables

4x*2)-((20x-52)=0

Wy multiply elements

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$

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