(4x+5)x(6x+1)=(8x+30)

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Solution for (4x+5)x(6x+1)=(8x+30) equation: 



(4x+5)x(6x+1)=(8x+30)

We move all terms to the left:

(4x+5)x(6x+1)-((8x+30))=0



We calculate terms in parentheses: -((8x+30)), so:

(8x+30)

We get rid of parentheses

8x+30

Back to the equation:

-(8x+30)



We get rid of parentheses

(4x+5)x(6x+1)-8x-30=0

We add all the numbers together, and all the variables

-8x+(4x+5)x(6x+1)-30=0

We move all terms containing x to the left, all other terms to the right

-8x+(4x+5)x(6x+1)=30

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