(4x+5)/13+36=41

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Solution for (4x+5)/13+36=41 equation: 



(4x+5)/13+36=41

We move all terms to the left:

(4x+5)/13+36-(41)=0

We add all the numbers together, and all the variables

(4x+5)/13-5=0

We multiply all the terms by the denominator


(4x+5)-5*13=0

We add all the numbers together, and all the variables

(4x+5)-65=0

We get rid of parentheses

4x+5-65=0

We add all the numbers together, and all the variables

4x-60=0

We move all terms containing x to the left, all other terms to the right

4x=60

x=60/4

x=15

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