(4x+5)+(3x-2)=143

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Solution for (4x+5)+(3x-2)=143 equation: 



(4x+5)+(3x-2)=143

We move all terms to the left:

(4x+5)+(3x-2)-(143)=0

We get rid of parentheses

4x+3x+5-2-143=0

We add all the numbers together, and all the variables

7x-140=0

We move all terms containing x to the left, all other terms to the right

7x=140

x=140/7

x=20

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