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(4x+5)(x-2)=-12
We move all terms to the left:
(4x+5)(x-2)-(-12)=0
We add all the numbers together, and all the variables
(4x+5)(x-2)+12=0
We multiply parentheses ..
(+4x^2-8x+5x-10)+12=0
We get rid of parentheses
4x^2-8x+5x-10+12=0
We add all the numbers together, and all the variables
4x^2-3x+2=0
a = 4; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·4·2
Δ = -23
Delta is less than zero, so there is no solution for the equation
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