(4x+5)(5x-5)(6x+10)(4x+10)+7x=540

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Solution for (4x+5)(5x-5)(6x+10)(4x+10)+7x=540 equation: 



(4x+5)(5x-5)(6x+10)(4x+10)+7x=540

We move all terms to the left:

(4x+5)(5x-5)(6x+10)(4x+10)+7x-(540)=0

We add all the numbers together, and all the variables

7x+(4x+5)(5x-5)(6x+10)(4x+10)-540=0

We multiply parentheses ..

(+20x^2-20x+25x-25)(6x+10)(4x+10)+7x-540=0

We multiply parentheses ..

(+20x^2-20x+25x-25)(+24x^2+60x+40x+100)+7x-540=0

We move all terms containing x to the left, all other terms to the right

(+20x^2-20x+25x-25)(+24x^2+60x+40x+100)+7x=540

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