(4x+4)/6=(2x-8)/2

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Solution for (4x+4)/6=(2x-8)/2 equation: 



(4x+4)/6=(2x-8)/2

We move all terms to the left:

(4x+4)/6-((2x-8)/2)=0

We calculate fractions


4x/()+(-((2x-8)*6)/()=0



We calculate terms in parentheses: +(-((2x-8)*6)/(), so:

-((2x-8)*6)/(

We multiply all the terms by the denominator


-((2x-8)*6)



We calculate terms in parentheses: -((2x-8)*6), so:

(2x-8)*6

We multiply parentheses

12x-48

Back to the equation:

-(12x-48)



We get rid of parentheses

-12x+48

Back to the equation:

+(-12x+48)



We get rid of parentheses

4x/()-12x+48=0

We multiply all the terms by the denominator


4x-12x*()+48*()=0

We add all the numbers together, and all the variables

4x-12x*()=0

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