(4x+4)+(4x-5)=71

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Solution for (4x+4)+(4x-5)=71 equation: 



(4x+4)+(4x-5)=71

We move all terms to the left:

(4x+4)+(4x-5)-(71)=0

We get rid of parentheses

4x+4x+4-5-71=0

We add all the numbers together, and all the variables

8x-72=0

We move all terms containing x to the left, all other terms to the right

8x=72

x=72/8

x=9

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