(4x+4)(2x-16)=180

Solution for (4x+4)(2x-16)=180 equation:

(4x+4)(2x-16)=180

We move all terms to the left:

(4x+4)(2x-16)-(180)=0

We multiply parentheses ..

(+8x^2-64x+8x-64)-180=0

We get rid of parentheses

8x^2-64x+8x-64-180=0

We add all the numbers together, and all the variables

8x^2-56x-244=0

a = 8; b = -56; c = -244;
Δ = b2-4ac
Δ = -562-4·8·(-244)
Δ = 10944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10944}=\sqrt{576*19}=\sqrt{576}*\sqrt{19}=24\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-24\sqrt{19}}{2*8}=\frac{56-24\sqrt{19}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+24\sqrt{19}}{2*8}=\frac{56+24\sqrt{19}}{16}
$