(4x+32)+(2x+40)=180

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Solution for (4x+32)+(2x+40)=180 equation: 



(4x+32)+(2x+40)=180

We move all terms to the left:

(4x+32)+(2x+40)-(180)=0

We get rid of parentheses

4x+2x+32+40-180=0

We add all the numbers together, and all the variables

6x-108=0

We move all terms containing x to the left, all other terms to the right

6x=108

x=108/6

x=18

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