(4x+3)/5x=1.2-(3/x)

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Solution for (4x+3)/5x=1.2-(3/x) equation: 



(4x+3)/5x=1.2-(3/x)

We move all terms to the left:

(4x+3)/5x-(1.2-(3/x))=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(4x+3)/5x-(1.2-(+3/x))=0

We calculate fractions


(4x+3)*x))/5x^2+(-(1.2-(+3*5x)/5x^2=0

We calculate fractions


((4x+3)*x))*5x^2)/(5x^2+(-(1.2*5x^2)+(-(+3*5x)*5x^2)/(5x^2+(-(1.2*5x^2)=0



We calculate terms in parentheses: +(-(+3*5x)*5x^2)/(5x^2+(-(1.2*5x^2), so:

-(+3*5x)*5x^2)/(5x^2+(-(1.2*5x^2

We multiply all the terms by the denominator


-(+3*5x)*5x^2)+((-(1.2*5x^2)*(5x^2

Back to the equation:

+(-(+3*5x)*5x^2)+((-(1.2*5x^2)*(5x^2)



We get rid of parentheses

((4x+3)*x))*5x^2)/(5x^2+(-1.2*5x^2+(-(+3*5x)*5x^2)+((-(1.2*5x^2)*5x^2=0

We multiply all the terms by the denominator


((4x+3)*x))*5x^2)-(1.2*5x^2)*(5x^2+(+((-(+3*5x)*5x^2))*(5x^2+(+(((-(1.2*5x^2)*5x^2)*(5x^2+(=0

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