(4x+3)/(5)=(7x-3)/(6)

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Solution for (4x+3)/(5)=(7x-3)/(6) equation: 



(4x+3)/(5)=(7x-3)/(6)

We move all terms to the left:

(4x+3)/(5)-((7x-3)/(6))=0

We calculate fractions


4x/()+(-((7x-3)*5)/()=0



We calculate terms in parentheses: +(-((7x-3)*5)/(), so:

-((7x-3)*5)/(

We multiply all the terms by the denominator


-((7x-3)*5)



We calculate terms in parentheses: -((7x-3)*5), so:

(7x-3)*5

We multiply parentheses

35x-15

Back to the equation:

-(35x-15)



We get rid of parentheses

-35x+15

Back to the equation:

+(-35x+15)



We get rid of parentheses

4x/()-35x+15=0

We multiply all the terms by the denominator


4x-35x*()+15*()=0

We add all the numbers together, and all the variables

4x-35x*()=0

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