(4x+3)+(6x-12)=180

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Solution for (4x+3)+(6x-12)=180 equation: 



(4x+3)+(6x-12)=180

We move all terms to the left:

(4x+3)+(6x-12)-(180)=0

We get rid of parentheses

4x+6x+3-12-180=0

We add all the numbers together, and all the variables

10x-189=0

We move all terms containing x to the left, all other terms to the right

10x=189

x=189/10

x=18+9/10

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