(4x+3)(2x+10)=0

Solution for (4x+3)(2x+10)=0 equation:

(4x+3)(2x+10)=0

We multiply parentheses ..

(+8x^2+40x+6x+30)=0

We get rid of parentheses

8x^2+40x+6x+30=0

We add all the numbers together, and all the variables

8x^2+46x+30=0

a = 8; b = 46; c = +30;
Δ = b2-4ac
Δ = 462-4·8·30
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-34}{2*8}=\frac{-80}{16}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+34}{2*8}=\frac{-12}{16}
=-3/4
$