(4x+28)=(9x-2)

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Solution for (4x+28)=(9x-2) equation: 



(4x+28)=(9x-2)

We move all terms to the left:

(4x+28)-((9x-2))=0

We get rid of parentheses

4x-((9x-2))+28=0



We calculate terms in parentheses: -((9x-2)), so:

(9x-2)

We get rid of parentheses

9x-2

Back to the equation:

-(9x-2)



We get rid of parentheses

4x-9x+2+28=0

We add all the numbers together, and all the variables

-5x+30=0

We move all terms containing x to the left, all other terms to the right

-5x=-30

x=-30/-5

x=+6

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