(4x+24)(7x+3)=360

Solution for (4x+24)(7x+3)=360 equation:

(4x+24)(7x+3)=360

We move all terms to the left:

(4x+24)(7x+3)-(360)=0

We multiply parentheses ..

(+28x^2+12x+168x+72)-360=0

We get rid of parentheses

28x^2+12x+168x+72-360=0

We add all the numbers together, and all the variables

28x^2+180x-288=0

a = 28; b = 180; c = -288;
Δ = b2-4ac
Δ = 1802-4·28·(-288)
Δ = 64656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{64656}=\sqrt{144*449}=\sqrt{144}*\sqrt{449}=12\sqrt{449}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-12\sqrt{449}}{2*28}=\frac{-180-12\sqrt{449}}{56}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+12\sqrt{449}}{2*28}=\frac{-180+12\sqrt{449}}{56}
$