(4x+22)+(10x-4)+(x+11)=180

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Solution for (4x+22)+(10x-4)+(x+11)=180 equation:



(4x+22)+(10x-4)+(x+11)=180
We move all terms to the left:
(4x+22)+(10x-4)+(x+11)-(180)=0
We get rid of parentheses
4x+10x+x+22-4+11-180=0
We add all the numbers together, and all the variables
15x-151=0
We move all terms containing x to the left, all other terms to the right
15x=151
x=151/15
x=10+1/15

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