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(4x+2)3-6(3x+4)=(x-7)5-12(x-1)
We move all terms to the left:
(4x+2)3-6(3x+4)-((x-7)5-12(x-1))=0
We multiply parentheses
12x-18x-((x-7)5-12(x-1))+6-24=0
We calculate terms in parentheses: -((x-7)5-12(x-1)), so:We add all the numbers together, and all the variables
(x-7)5-12(x-1)
We multiply parentheses
5x-12x-35+12
We add all the numbers together, and all the variables
-7x-23
Back to the equation:
-(-7x-23)
-6x-(-7x-23)-18=0
We get rid of parentheses
-6x+7x+23-18=0
We add all the numbers together, and all the variables
x+5=0
We move all terms containing x to the left, all other terms to the right
x=-5
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