(4x+2)+(x+112)+(x+6)=180

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Solution for (4x+2)+(x+112)+(x+6)=180 equation: 



(4x+2)+(x+112)+(x+6)=180

We move all terms to the left:

(4x+2)+(x+112)+(x+6)-(180)=0

We get rid of parentheses

4x+x+x+2+112+6-180=0

We add all the numbers together, and all the variables

6x-60=0

We move all terms containing x to the left, all other terms to the right

6x=60

x=60/6

x=10

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