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(4x+14)(2x-8)=0
We multiply parentheses ..
(+8x^2-32x+28x-112)=0
We get rid of parentheses
8x^2-32x+28x-112=0
We add all the numbers together, and all the variables
8x^2-4x-112=0
a = 8; b = -4; c = -112;
Δ = b2-4ac
Δ = -42-4·8·(-112)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-60}{2*8}=\frac{-56}{16} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+60}{2*8}=\frac{64}{16} =4 $
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