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(4x+11)=(x*x-10)
We move all terms to the left:
(4x+11)-((x*x-10))=0
We get rid of parentheses
4x-((x*x-10))+11=0
We calculate terms in parentheses: -((x*x-10)), so:We get rid of parentheses
(x*x-10)
We get rid of parentheses
x*x-10
Wy multiply elements
x^2-10
Back to the equation:
-(x^2-10)
-x^2+4x+10+11=0
We add all the numbers together, and all the variables
-1x^2+4x+21=0
a = -1; b = 4; c = +21;
Δ = b2-4ac
Δ = 42-4·(-1)·21
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-10}{2*-1}=\frac{-14}{-2} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+10}{2*-1}=\frac{6}{-2} =-3 $
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