(4x+11)*(5x-10)=0

Solution for (4x+11)*(5x-10)=0 equation:

(4x+11)(5x-10)=0

We multiply parentheses ..

(+20x^2-40x+55x-110)=0

We get rid of parentheses

20x^2-40x+55x-110=0

We add all the numbers together, and all the variables

20x^2+15x-110=0

a = 20; b = 15; c = -110;
Δ = b2-4ac
Δ = 152-4·20·(-110)
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9025}=95$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-95}{2*20}=\frac{-110}{40}
=-2+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+95}{2*20}=\frac{80}{40}
=2
$