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(4x+11)(12x-24)=0
We multiply parentheses ..
(+48x^2-96x+132x-264)=0
We get rid of parentheses
48x^2-96x+132x-264=0
We add all the numbers together, and all the variables
48x^2+36x-264=0
a = 48; b = 36; c = -264;
Δ = b2-4ac
Δ = 362-4·48·(-264)
Δ = 51984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{51984}=228$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-228}{2*48}=\frac{-264}{96} =-2+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+228}{2*48}=\frac{192}{96} =2 $
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