(4x+10)+(3x-5)=33

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Solution for (4x+10)+(3x-5)=33 equation: 



(4x+10)+(3x-5)=33

We move all terms to the left:

(4x+10)+(3x-5)-(33)=0

We get rid of parentheses

4x+3x+10-5-33=0

We add all the numbers together, and all the variables

7x-28=0

We move all terms containing x to the left, all other terms to the right

7x=28

x=28/7

x=4

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