(4x+1)/(3)=(x-5)/(2)

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Solution for (4x+1)/(3)=(x-5)/(2) equation: 



(4x+1)/(3)=(x-5)/(2)

We move all terms to the left:

(4x+1)/(3)-((x-5)/(2))=0

We calculate fractions


4x/()+(-((x-5)*3)/()=0



We calculate terms in parentheses: +(-((x-5)*3)/(), so:

-((x-5)*3)/(

We multiply all the terms by the denominator


-((x-5)*3)



We calculate terms in parentheses: -((x-5)*3), so:

(x-5)*3

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We get rid of parentheses

-3x+15

Back to the equation:

+(-3x+15)



We get rid of parentheses

4x/()-3x+15=0

We multiply all the terms by the denominator


4x-3x*()+15*()=0

We add all the numbers together, and all the variables

4x-3x*()=0

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