(4x+1)-(-x-3)=(6x+1)+(x-7)

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Solution for (4x+1)-(-x-3)=(6x+1)+(x-7) equation:



(4x+1)-(-x-3)=(6x+1)+(x-7)
We move all terms to the left:
(4x+1)-(-x-3)-((6x+1)+(x-7))=0
We add all the numbers together, and all the variables
(4x+1)-(-1x-3)-((6x+1)+(x-7))=0
We get rid of parentheses
4x+1x-((6x+1)+(x-7))+1+3=0
We calculate terms in parentheses: -((6x+1)+(x-7)), so:
(6x+1)+(x-7)
We get rid of parentheses
6x+x+1-7
We add all the numbers together, and all the variables
7x-6
Back to the equation:
-(7x-6)
We add all the numbers together, and all the variables
5x-(7x-6)+4=0
We get rid of parentheses
5x-7x+6+4=0
We add all the numbers together, and all the variables
-2x+10=0
We move all terms containing x to the left, all other terms to the right
-2x=-10
x=-10/-2
x=+5

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