(4x+1)+(6x-3)=78

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Solution for (4x+1)+(6x-3)=78 equation: 



(4x+1)+(6x-3)=78

We move all terms to the left:

(4x+1)+(6x-3)-(78)=0

We get rid of parentheses

4x+6x+1-3-78=0

We add all the numbers together, and all the variables

10x-80=0

We move all terms containing x to the left, all other terms to the right

10x=80

x=80/10

x=8

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