(4x+1)+(3x-8)=105

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Solution for (4x+1)+(3x-8)=105 equation: 



(4x+1)+(3x-8)=105

We move all terms to the left:

(4x+1)+(3x-8)-(105)=0

We get rid of parentheses

4x+3x+1-8-105=0

We add all the numbers together, and all the variables

7x-112=0

We move all terms containing x to the left, all other terms to the right

7x=112

x=112/7

x=16

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