(4x+1)+(12x-29)=180

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Solution for (4x+1)+(12x-29)=180 equation: 



(4x+1)+(12x-29)=180

We move all terms to the left:

(4x+1)+(12x-29)-(180)=0

We get rid of parentheses

4x+12x+1-29-180=0

We add all the numbers together, and all the variables

16x-208=0

We move all terms containing x to the left, all other terms to the right

16x=208

x=208/16

x=13

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