(4x+1)(x+3)=45x-61

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Solution for (4x+1)(x+3)=45x-61 equation: 



(4x+1)(x+3)=45x-61

We move all terms to the left:

(4x+1)(x+3)-(45x-61)=0

We get rid of parentheses

(4x+1)(x+3)-45x+61=0

We multiply parentheses ..

(+4x^2+12x+x+3)-45x+61=0

We get rid of parentheses

4x^2+12x+x-45x+3+61=0

We add all the numbers together, and all the variables

4x^2-32x+64=0

a = 4; b = -32; c = +64;
Δ = b2-4ac
Δ = -322-4·4·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{32}{8}=4$

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