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(4x+1)(x+3)-5x=(2x+3)(2x+5)-4(2x+3)
We move all terms to the left:
(4x+1)(x+3)-5x-((2x+3)(2x+5)-4(2x+3))=0
We add all the numbers together, and all the variables
-5x+(4x+1)(x+3)-((2x+3)(2x+5)-4(2x+3))=0
We multiply parentheses ..
(+4x^2+12x+x+3)-5x-((2x+3)(2x+5)-4(2x+3))=0
We calculate terms in parentheses: -((2x+3)(2x+5)-4(2x+3)), so:We get rid of parentheses
(2x+3)(2x+5)-4(2x+3)
We multiply parentheses
(2x+3)(2x+5)-8x-12
We multiply parentheses ..
(+4x^2+10x+6x+15)-8x-12
We get rid of parentheses
4x^2+10x+6x-8x+15-12
We add all the numbers together, and all the variables
4x^2+8x+3
Back to the equation:
-(4x^2+8x+3)
4x^2-4x^2+12x+x-5x-8x+3-3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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