(4x+1)(4x-1)x=-3

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Solution for (4x+1)(4x-1)x=-3 equation: 



(4x+1)(4x-1)x=-3

We move all terms to the left:

(4x+1)(4x-1)x-(-3)=0

We add all the numbers together, and all the variables

(4x+1)(4x-1)x+3=0

We use the square of the difference formula

16x^2-1+3=0

We add all the numbers together, and all the variables

16x^2+2=0

a = 16; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·16·2
Δ = -128
Delta is less than zero, so there is no solution for the equation

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