(4x+1)(4x+1)=(4x+1)(4x+1)

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Solution for (4x+1)(4x+1)=(4x+1)(4x+1) equation: 



(4x+1)(4x+1)=(4x+1)(4x+1)

We move all terms to the left:

(4x+1)(4x+1)-((4x+1)(4x+1))=0

We multiply parentheses ..

(+16x^2+4x+4x+1)-((+16x^2+4x+4x+1))=0



We calculate terms in parentheses: -((+16x^2+4x+4x+1)), so:

(+16x^2+4x+4x+1)

We get rid of parentheses

16x^2+4x+4x+1

We add all the numbers together, and all the variables

16x^2+8x+1

Back to the equation:

-(16x^2+8x+1)



We get rid of parentheses

16x^2-16x^2+4x+4x-8x+1-1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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