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(4x+1)(3x+11)=180
We move all terms to the left:
(4x+1)(3x+11)-(180)=0
We multiply parentheses ..
(+12x^2+44x+3x+11)-180=0
We get rid of parentheses
12x^2+44x+3x+11-180=0
We add all the numbers together, and all the variables
12x^2+47x-169=0
a = 12; b = 47; c = -169;
Δ = b2-4ac
Δ = 472-4·12·(-169)
Δ = 10321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{10321}}{2*12}=\frac{-47-\sqrt{10321}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{10321}}{2*12}=\frac{-47+\sqrt{10321}}{24} $
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