(4x)/(5x)=(6x+4)/(8x-15)

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Solution for (4x)/(5x)=(6x+4)/(8x-15) equation: 



(4x)/(5x)=(6x+4)/(8x-15)

We move all terms to the left:

(4x)/(5x)-((6x+4)/(8x-15))=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: (8x-15))!=0

x∈R



We calculate fractions


(-28x^2)/(-35x^2)+(-((6x+4)*5x)/(-35x^2)=0



We calculate terms in parentheses: +(-((6x+4)*5x)/(-35x^2), so:

-((6x+4)*5x)/(-35x^2

We multiply all the terms by the denominator


-((6x+4)*5x)



We calculate terms in parentheses: -((6x+4)*5x), so:

(6x+4)*5x

We multiply parentheses

30x^2+20x

Back to the equation:

-(30x^2+20x)



We get rid of parentheses

-30x^2-20x

Back to the equation:

+(-30x^2-20x)



We get rid of parentheses

(-28x^2)/(-35x^2)-30x^2-20x=0

We multiply all the terms by the denominator


(-28x^2)-30x^2*(-35x^2)-20x*(-35x^2)=0

We multiply parentheses

(-28x^2)-30x^2*(-35x^2)+700x^3=0

We get rid of parentheses

-28x^2-30x^2*(-35x^2)+700x^3=0

We do not support expression: x^3

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