(4x)/(5x)=(4x+8)/(6x-10)

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Solution for (4x)/(5x)=(4x+8)/(6x-10) equation: 



(4x)/(5x)=(4x+8)/(6x-10)

We move all terms to the left:

(4x)/(5x)-((4x+8)/(6x-10))=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: (6x-10))!=0

x∈R



We calculate fractions


(-16x^2)/(-20x^2)+(-((4x+8)*5x)/(-20x^2)=0



We calculate terms in parentheses: +(-((4x+8)*5x)/(-20x^2), so:

-((4x+8)*5x)/(-20x^2

We multiply all the terms by the denominator


-((4x+8)*5x)



We calculate terms in parentheses: -((4x+8)*5x), so:

(4x+8)*5x

We multiply parentheses

20x^2+40x

Back to the equation:

-(20x^2+40x)



We get rid of parentheses

-20x^2-40x

Back to the equation:

+(-20x^2-40x)



We get rid of parentheses

(-16x^2)/(-20x^2)-20x^2-40x=0

We multiply all the terms by the denominator


(-16x^2)-20x^2*(-20x^2)-40x*(-20x^2)=0

We multiply parentheses

(-16x^2)-20x^2*(-20x^2)+800x^3=0

We get rid of parentheses

-16x^2-20x^2*(-20x^2)+800x^3=0

We do not support expression: x^3

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