(4x)+(x+6)+(3x-2)=180

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Solution for (4x)+(x+6)+(3x-2)=180 equation: 



(4x)+(x+6)+(3x-2)=180

We move all terms to the left:

(4x)+(x+6)+(3x-2)-(180)=0

We get rid of parentheses

4x+x+3x+6-2-180=0

We add all the numbers together, and all the variables

8x-176=0

We move all terms containing x to the left, all other terms to the right

8x=176

x=176/8

x=22

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