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(4x)+(4/x)=10
We move all terms to the left:
(4x)+(4/x)-(10)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4x+(+4/x)-10=0
We get rid of parentheses
4x+4/x-10=0
We multiply all the terms by the denominator
4x*x-10*x+4=0
We add all the numbers together, and all the variables
-10x+4x*x+4=0
Wy multiply elements
4x^2-10x+4=0
a = 4; b = -10; c = +4;
Δ = b2-4ac
Δ = -102-4·4·4
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-6}{2*4}=\frac{4}{8} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+6}{2*4}=\frac{16}{8} =2 $
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